| ⇦ | 
| ⇨ |
The number of optical isomers formed by hydrogenation of the compound (CH₃)₂C=CHCH₃ are
Options
(a) 2
(b) 3
(c) 4
(d) zero
Correct Answer:
zero
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The correct order of increasing bond length of C–H, C–O, C–C and C=C is
- Which of the following compounds possesses the C-H bond with the lowest bond dissociation
- Which of the following is a strong acid
- The strength of H₂O₂ (in g/litre) in 11.2 volume solution of H₂O₂ is
- During the decomposition of H₂O₂ to give oxygen, 48 g O₂ is formed per minute
Topics: Hydrocarbons
(84)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The correct order of increasing bond length of C–H, C–O, C–C and C=C is
- Which of the following compounds possesses the C-H bond with the lowest bond dissociation
- Which of the following is a strong acid
- The strength of H₂O₂ (in g/litre) in 11.2 volume solution of H₂O₂ is
- During the decomposition of H₂O₂ to give oxygen, 48 g O₂ is formed per minute
Topics: Hydrocarbons (84)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
It is because none of the carbon atoms are chiral(different substituents on the same C atom).