| ⇦ | 
| ⇨ |
The motion of a particle along a straight line is described by equation : x= 8 + 12t– t³ where x is in metre and t in second. The retardation of the particle when its velocity becomes zero, is :
Options
(a) 24 ms⁻²
(b) zero
(c) 6ms⁻²
(d) 12 ms⁻²
Correct Answer:
12 ms⁻²
Explanation:
x = 8 + 12t – t³ The final velocity of the particle will be zero, because it retarded.
V= 0 + 12 – 3t² = 0 ⇒ 3t² = 12 ⇒ t = 2 sec
Now the retardation a = dv/ dt = 0 – 6t
a [ t= 2] = – 12 m/s²
retardation = 12 m/s²
Related Questions: - When the rate of flow of charge through a metallic conductor
- In a vessel, the gas is at a pressure P. If the mass of all the molecules
- In the adiabatic compression, the decrease in volume associated with
- If the length of a stretched string is shortened by 4% and the tension is increased
- A particle with charge q is moving along a circle of radius R with unoform speed v.
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When the rate of flow of charge through a metallic conductor
- In a vessel, the gas is at a pressure P. If the mass of all the molecules
- In the adiabatic compression, the decrease in volume associated with
- If the length of a stretched string is shortened by 4% and the tension is increased
- A particle with charge q is moving along a circle of radius R with unoform speed v.
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply