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The motion of a particle along a straight line is described by equation : x= 8 + 12t– t³ where x is in metre and t in second. The retardation of the particle when its velocity becomes zero, is :
Options
(a) 24 ms⁻²
(b) zero
(c) 6ms⁻²
(d) 12 ms⁻²
Correct Answer:
12 ms⁻²
Explanation:
x = 8 + 12t – t³ The final velocity of the particle will be zero, because it retarded.
V= 0 + 12 – 3t² = 0 ⇒ 3t² = 12 ⇒ t = 2 sec
Now the retardation a = dv/ dt = 0 – 6t
a [ t= 2] = – 12 m/s²
retardation = 12 m/s²
Related Questions: - An aeroplane is flying horizontally with a velocity of 216 km/h at a height of 1960 m.
- Two particles A and B having equal charges +6C, after being accelerated
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An aeroplane is flying horizontally with a velocity of 216 km/h at a height of 1960 m.
- Two particles A and B having equal charges +6C, after being accelerated
- If the density of earth is doubled keeping its radius constant then acceleration
- If L and C denote inductance and capacitance,then the dimensions of L-C are
- The first line in Lyman series has wavelength λ. The wavelength
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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