⇦ | ⇨ |
The most probable radius (in pm) for finding the electron in He⁺ is
Options
(a) 0
(b) 52.9
(c) 26.5
(d) 105.8
Correct Answer:
26.5
Explanation:
Most probable radius = a₀ / Z
where a₀ = 52.9 pm.
For helium ion, Z = 2.
r(mp) = 52.9 / 2 = 26.45 pm.
Related Questions: - Correct relation between dissociation constant of a dibasic acid is
- A gas decolourised by KMnO₄ solution but gives no precipitate with ammoniacal cuprous
- Aspirin is a acetylated product is
- Which of the following gases is not a greenhouse gas
- Which of the following is the strongest oxidising agent
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Correct relation between dissociation constant of a dibasic acid is
- A gas decolourised by KMnO₄ solution but gives no precipitate with ammoniacal cuprous
- Aspirin is a acetylated product is
- Which of the following gases is not a greenhouse gas
- Which of the following is the strongest oxidising agent
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply