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The momentum of a photon of energy 1 MeV in kg m/s will be
Options
(a) 5 x 10⁻²²
(b) 0.33 x 10⁶
(c) 7 x10⁻²⁴
(d) 10⁻²²
Correct Answer:
5 x 10⁻²²
Explanation:
Energy of photon E = 1 MeV
Momentum of photon p = E / c
p = E / c = (1 × 10⁶ × 1.6 × 10⁻¹⁹J) / 3 × 10⁸ ms⁻¹
= 0.53 × 10⁻²¹ = 5 × 10⁻²² kg m/s.
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The Rutherford scattering experiment proves that an atom consists of
- A wire mesh consisting of very small squares is viewed at a distance
- Excitation energy of a hydrogen like ion, in its first excitation state, is 40.8 eV.
- A light of wavelength 5000Å falls on a sensitive plate with photoelectric work
- Two coils of self inductance 2 mH and 8 mH are placed so close together
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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