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The momentum of a body is increased by 20%.The percentage increases in kinetic energy is
Options
(a) 54 %
(b) 44 %
(c) 100 %
(d) 50 %
Correct Answer:
44 %
Explanation:
Increase in KE = p²/2m
New momentum = p + p/5 = 6p/5
KE(f) = [(6/5).p]²/2m = (36/25).(p²/2m)
ΔKE = (36/25).(p²/2m) – (p²/2m) = (11p²/252m)
Percentage increase = 44%
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When a charged oil drop moves upwards in an electric field,
- An object is placed 30 cm away from a convex lens of focal length 10 cm and a sharp
- If longitudinal strain for a wire is 0.03 and its poisson’s ratio is 0.5
- Curie is the unit of
- The ionisation energy of hydrogen is 13.6 eV. The energy of the photon released
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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