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The momentum of a body is increased by 20%.The percentage increases in kinetic energy is
Options
(a) 54 %
(b) 44 %
(c) 100 %
(d) 50 %
Correct Answer:
44 %
Explanation:
Increase in KE = p²/2m
New momentum = p + p/5 = 6p/5
KE(f) = [(6/5).p]²/2m = (36/25).(p²/2m)
ΔKE = (36/25).(p²/2m) – (p²/2m) = (11p²/252m)
Percentage increase = 44%
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If a mass of 20g having charge 3.0 mC moving with velocity 20ms⁻¹ enters a region
- In Young’s double slit experiment, the wavelength of the light used is doubled
- A road of width 20 m forms an arc of radius 15 m,its outer edge is 2m higher than
- When a metallic surface is illuminated with radiation of wavelength λ,
- Fusion reaction takes place at high temperature because
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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