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The momentum of a body is increased by 20%.The percentage increases in kinetic energy is
Options
(a) 54 %
(b) 44 %
(c) 100 %
(d) 50 %
Correct Answer:
44 %
Explanation:
Increase in KE = p²/2m
New momentum = p + p/5 = 6p/5
KE(f) = [(6/5).p]²/2m = (36/25).(p²/2m)
ΔKE = (36/25).(p²/2m) – (p²/2m) = (11p²/252m)
Percentage increase = 44%
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Sodium and copper have work function 2.3 eV and 4.5 eV respectively
- A particle moving in a straight line with uniform acceleration is observed
- If the ionisation energy for the hydrogen atom is 13.6 eV, the energy required
- If h is Planck’s constant, the momentum of a photon of wavelength 0.01 Å is
- 40 g of Argon is heated from 40⁰C to 100⁰C (R=2 cal/mole). Heat absorbed at constant
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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