| ⇦ |
| ⇨ |
The momentum of a body is increased by 20%.The percentage increases in kinetic energy is
Options
(a) 54 %
(b) 44 %
(c) 100 %
(d) 50 %
Correct Answer:
44 %
Explanation:
Increase in KE = p²/2m
New momentum = p + p/5 = 6p/5
KE(f) = [(6/5).p]²/2m = (36/25).(p²/2m)
ΔKE = (36/25).(p²/2m) – (p²/2m) = (11p²/252m)
Percentage increase = 44%
Related Questions: - When a light beam of frequency v is incident on a metal surface,
- If by mistake voltmeter is connected in series and ammeter in parallel then
- The width of the diffraction band varies
- A force of 5 N is acting on an object. Displacement of object is 10 m and the work done
- The escape velocity of a body on an imaginary planet which is thrice the radius
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When a light beam of frequency v is incident on a metal surface,
- If by mistake voltmeter is connected in series and ammeter in parallel then
- The width of the diffraction band varies
- A force of 5 N is acting on an object. Displacement of object is 10 m and the work done
- The escape velocity of a body on an imaginary planet which is thrice the radius
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply