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The momentum of a body is increased by 20%.The percentage increases in kinetic energy is
Options
(a) 54 %
(b) 44 %
(c) 100 %
(d) 50 %
Correct Answer:
44 %
Explanation:
Increase in KE = p²/2m
New momentum = p + p/5 = 6p/5
KE(f) = [(6/5).p]²/2m = (36/25).(p²/2m)
ΔKE = (36/25).(p²/2m) – (p²/2m) = (11p²/252m)
Percentage increase = 44%
Related Questions: - The necessary condition in making of a junction transistor
- Two particles A and B having equal charges, after being accelerated
- If ∆Q>0 when heat flows into a system, ∆W>0 when work is done on the system
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Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The necessary condition in making of a junction transistor
- Two particles A and B having equal charges, after being accelerated
- If ∆Q>0 when heat flows into a system, ∆W>0 when work is done on the system
- Which of the following physical quantities has neither dimensions nor unit
- Light with an energy flux of 25×10⁴ Wm⁻² falls on a perfectly reflecting surface
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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