The moment of inertia of a uniform circular disc of radius R and mass M about an axis

The moment of inertia of a uniform circular disc of radius R and mass M about an axis touching the disc at its diameter and normal to the disc

Options

(a) 1/2 MR²
(b) MR²
(c) 2/5 MR²
(d) 3/2 MR²

Correct Answer:

3/2 MR²

Explanation:

Moment of inertia of a uniform circular disc about an axis through its centre and perpendicular of its plane is,
Ic = (1/2) MR²
By the theorem of parallel axes,
Therefore, moment of inertia of a uniform circular disc about an axis touching the disc at its diameter and normal to the disc is I.
I = Ic + Mh² = (1/2) MR² + MR² = (3/2) MR².

admin:

Related Questions

  1. A proton and an alpha particle both enter a region of uniform magnetic field B,
  2. A particle of mass 1 mg has the same wavelength as an electron moving with a velocity
  3. The velocity of a particle at an instant is 10 ms⁻¹ and after 5 s the velocity
  4. A thermodynamic system undergoes cyclic process ABCDA as shown in figure
  5. The difference in the lengths of a mean solar day and a sidereal day is about