| ⇦ | 
| ⇨ |
The moment of inertia of a uniform circular disc of radius R and mass M about an axis touching the disc at its diameter and normal to the disc
Options
(a) 1/2 MR²
(b) MR²
(c) 2/5 MR²
(d) 3/2 MR²
Correct Answer:
3/2 MR²
Explanation:
Moment of inertia of a uniform circular disc about an axis through its centre and perpendicular of its plane is,
Ic = (1/2) MR²
By the theorem of parallel axes,
Therefore, moment of inertia of a uniform circular disc about an axis touching the disc at its diameter and normal to the disc is I.
I = Ic + Mh² = (1/2) MR² + MR² = (3/2) MR².
Related Questions: - Two parallel beams of positron moving in the same direction will
- A soap bubble oscillates with time period T, which in turn depends on the pressure
- The wavelength of the first line of Lymasn series for hydrogen atom is equal
- Two strings A and B, made of same material are stretched by same tension
- Wave nature of light is verified by
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two parallel beams of positron moving in the same direction will
- A soap bubble oscillates with time period T, which in turn depends on the pressure
- The wavelength of the first line of Lymasn series for hydrogen atom is equal
- Two strings A and B, made of same material are stretched by same tension
- Wave nature of light is verified by
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply