| ⇦ |
| ⇨ |
The moment of inertia of a uniform circular disc of radius R and mass M about an axis touching the disc at its diameter and normal to the disc
Options
(a) 1/2 MR²
(b) MR²
(c) 2/5 MR²
(d) 3/2 MR²
Correct Answer:
3/2 MR²
Explanation:
Moment of inertia of a uniform circular disc about an axis through its centre and perpendicular of its plane is,
Ic = (1/2) MR²
By the theorem of parallel axes,
Therefore, moment of inertia of a uniform circular disc about an axis touching the disc at its diameter and normal to the disc is I.
I = Ic + Mh² = (1/2) MR² + MR² = (3/2) MR².
Related Questions: - A body of mass 10 kg is moving on an inclined plane of inclination 30°with an acceleration
- Which of the following is a vector quantity?
- Efficiency of a Carnot engine is 50% when temperature of sink is 500K. In order
- A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns per cm length
- A disc of moment of inertia (9.8/π²) kg m² is rotating at 600 rpm. If the frequency
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body of mass 10 kg is moving on an inclined plane of inclination 30°with an acceleration
- Which of the following is a vector quantity?
- Efficiency of a Carnot engine is 50% when temperature of sink is 500K. In order
- A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns per cm length
- A disc of moment of inertia (9.8/π²) kg m² is rotating at 600 rpm. If the frequency
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply