⇦ | ![]() | ⇨ |
The moment of inertia of a uniform circular disc of radius R and mass M about an axis touching the disc at its diameter and normal to the disc
Options
(a) 1/2 MR²
(b) MR²
(c) 2/5 MR²
(d) 3/2 MR²
Correct Answer:
3/2 MR²
Explanation:
Moment of inertia of a uniform circular disc about an axis through its centre and perpendicular of its plane is,
Ic = (1/2) MR²
By the theorem of parallel axes,
Therefore, moment of inertia of a uniform circular disc about an axis touching the disc at its diameter and normal to the disc is I.
I = Ic + Mh² = (1/2) MR² + MR² = (3/2) MR².
Related Questions:
- The ratio of the nuclear radii of elements with mass numbers 216 and 125 is
- A cyclotron is used to accelerate
- A person has a minimum distance of distinct vision as 50 cm. The power of lenses
- A small part of the rim of a fly wheel breaks off while it is rotating at a constant
- If 20% of a radiactive element decays in 10 days, then amount of original material left
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply