| ⇦ | 
| ⇨ |
The moment of inertia of a thin uniform rod of mass M and length L about an axis passing through its midpoint and perpendicular to its length is Iₒ. Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is
Options
(a) Iₒ + ML² / 2
(b) Iₒ + ML² / 4
(c) Iₒ + 2ML²
(d) Iₒ + ML²
Correct Answer:
Iₒ + ML² / 4
Explanation:
By theorem of parallel axes,
I = Icm + Md²
I = Iₒ + M(L / 2)²
Iₒ + ML² / 4
Related Questions: - The polarising angle of glass is 57⁰. A ray of light which is incident at this angle
- Calculate the charge on equivalent capacitance of the conbination shown in figure
- Magnetic induction produced at the centre of a circular loop carrying current is B.
- Light emitted during the de excitation of electron from n=3 to n=2, when incident
- If the feedback voltage is increased in a negative feedback amplifier, then
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The polarising angle of glass is 57⁰. A ray of light which is incident at this angle
- Calculate the charge on equivalent capacitance of the conbination shown in figure
- Magnetic induction produced at the centre of a circular loop carrying current is B.
- Light emitted during the de excitation of electron from n=3 to n=2, when incident
- If the feedback voltage is increased in a negative feedback amplifier, then
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply