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The molar specific heats of an ideal gas at constant pressure and volume are denoted by Cp and Cv, respectively. If γ = Cp/Cv and R is the universal gas constant, then Cv is equal to
Options
(a) R / ( γ – 1)
(b) (γ – 1) / R
(c) γ R
(d) 1 + γ / 1 – γ
Correct Answer:
R / ( γ – 1)
Explanation:
Cₚ – Cᵥ = R ⇒ Cₚ = Cᵥ + R
γ = Cₚ / Cᵥ = Cᵥ + R / Cᵥ = Cᵥ / Cᵥ + R / Cᵥ
⇒ γ = 1 + R / Cᵥ ⇒ R / Cᵥ = γ – 1
⇒ Cᵥ = R / γ – 1
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Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle is under two mutually perpendicular simple harmonic motions
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Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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