| ⇦ | 
| ⇨ |
The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
Related Questions: - An iron rod of volume 10⁻⁴ m³ and relative permeability 1000 is placed inside a long
- A uniform electric field and uniform magnetic field are acting along the same
- The net electric force on a charge of +3μC at the mid-point on the line joining two
- The product of pressure and volume hve thesame units as the product of
- Consider the following two statements about Kirchhoff’s law
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An iron rod of volume 10⁻⁴ m³ and relative permeability 1000 is placed inside a long
- A uniform electric field and uniform magnetic field are acting along the same
- The net electric force on a charge of +3μC at the mid-point on the line joining two
- The product of pressure and volume hve thesame units as the product of
- Consider the following two statements about Kirchhoff’s law
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply