| ⇦ | 
| ⇨ |
The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
Related Questions: - Three masses are placed on the x-axis : 300 g at origin, 500 g at x = 40 cm
- A coil of self-inductance L is connected in series with a bulb B and an AC source
- Two circuits have a mutual inductance of 0.1 H. What average e.m.f. is induced
- A thin rod of length L and mass M is held vertically with one end on the floor
- Two bodies A and B having temperature 327° C and 427° C are radiating heat
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three masses are placed on the x-axis : 300 g at origin, 500 g at x = 40 cm
- A coil of self-inductance L is connected in series with a bulb B and an AC source
- Two circuits have a mutual inductance of 0.1 H. What average e.m.f. is induced
- A thin rod of length L and mass M is held vertically with one end on the floor
- Two bodies A and B having temperature 327° C and 427° C are radiating heat
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply