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The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A pan is suspended from a steel wire. Weights are slowly put on the pan
- A battery of e.m.f. E and internal resistance r is connected to an external resistance
- In which process, the P-V indicator diagram is a straight line parallel to volume
- A radioactive nucleus emits a beta particle. The parent and daughter nuclei are
- A 2 kg mass starts from rest on an inclined smooth surface with inclination
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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