⇦ | ⇨ |
The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
Related Questions: - Element ²³⁴U has 92 protons and 234 nucleons in its nucleus. It decays by
- Identify the wrong statement
- A particle moves along the x-axis such that its co-ordinate (x) varies with time (t)
- If the error in the measurement of momentum of particle is (+100%)
- The distance travelled by a particle starting from rest and moving with an acceleration
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Element ²³⁴U has 92 protons and 234 nucleons in its nucleus. It decays by
- Identify the wrong statement
- A particle moves along the x-axis such that its co-ordinate (x) varies with time (t)
- If the error in the measurement of momentum of particle is (+100%)
- The distance travelled by a particle starting from rest and moving with an acceleration
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply