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The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
Related Questions: - The threshold frequency for a photosensitive metal is 3.3 x 10¹⁴ Hz.
- A particle is moving with a uniform velocity along a straight line path
- The refracting angle of a prism is A and refractive index of the material of the prism
- Which one of the following electrical meter has the smallest resistance?
- In an NPN transistor the collector current is 24 mA. If 80% of the electrons
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The threshold frequency for a photosensitive metal is 3.3 x 10¹⁴ Hz.
- A particle is moving with a uniform velocity along a straight line path
- The refracting angle of a prism is A and refractive index of the material of the prism
- Which one of the following electrical meter has the smallest resistance?
- In an NPN transistor the collector current is 24 mA. If 80% of the electrons
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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