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The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electric dipole of length 1 cm is placed with the axis making an angle of 30⁰
- A spherical liquid drop of radius R is divided into 8 equal droplets. If the surface
- A proton carrying 1 MeV kinetic energy is moving in a circular path of radius
- The resistance of a wire is 5 ohm at 50° C and 6 ohm at 100° C. The resistance
- If a mass of 20g having charge 3.0 mC moving with velocity 20ms⁻¹ enters a region
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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