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The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
Related Questions: - A current of 5 A is passing through a metallic wire of cross-sectional area 4×10⁻⁶ m².
- A body is thrown upward from ground covers equal distances
- A bucket full of water is revolved in a vertical circle of 2m
- A resistance of 20 ohm is connected to a source of an alternating potential V
- Two wires of the same dimensions but resistivities p1 and p2 are connected in series
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A current of 5 A is passing through a metallic wire of cross-sectional area 4×10⁻⁶ m².
- A body is thrown upward from ground covers equal distances
- A bucket full of water is revolved in a vertical circle of 2m
- A resistance of 20 ohm is connected to a source of an alternating potential V
- Two wires of the same dimensions but resistivities p1 and p2 are connected in series
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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