| ⇦ | 
| ⇨ |
The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T. A proton is shot into the field with velocity v=(2×10⁵i ̂ + 4×10⁵ j ̂ ) m/s. The proton follows a helical path in the field. The distance moved by proton in the x-direction during the period of one revolution in the yz- plane will be (mss of proton=1.67×10⁻²⁷ kg)
Options
(a) 0.053 m
(b) 0.136 m
(c) 0.157 m
(d) 0.236 m
Correct Answer:
0.157 m
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The period of oscillation of a mass M suspended from a spring of negligible mass is T
- Charge Q is divided into two parts which are then kept some distance apart. The force
- An electron of a stationary hydrogen atom passes from the fifth energy level to
- A particle A suffers on oblique elastic collision with a particle B that
- In electromagnetic spectrum, the frequencies of γ-rays and x-rays and ultraviolet rays
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The period of oscillation of a mass M suspended from a spring of negligible mass is T
- Charge Q is divided into two parts which are then kept some distance apart. The force
- An electron of a stationary hydrogen atom passes from the fifth energy level to
- A particle A suffers on oblique elastic collision with a particle B that
- In electromagnetic spectrum, the frequencies of γ-rays and x-rays and ultraviolet rays
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply