| ⇦ | 
| ⇨ |
The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T. A proton is shot into the field with velocity v=(2×10⁵i ̂ + 4×10⁵ j ̂ ) m/s. The proton follows a helical path in the field. The distance moved by proton in the x-direction during the period of one revolution in the yz- plane will be (mss of proton=1.67×10⁻²⁷ kg)
Options
(a) 0.053 m
(b) 0.136 m
(c) 0.157 m
(d) 0.236 m
Correct Answer:
0.157 m
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A sound absorber attenuates the sound level by 20 dB. The intensity decreases
- The pressure at the bottom of a tank containing a liquid does not depend on
- Water falls from a height of 60m at the rate of 15 kg/s to operate a turbine
- An alternating electric field, of frequency v, is applied across the dees (radius = R)
- The velocity of radio-waves is 3×10⁵ km/s. The frequency corresponding to wavelength
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A sound absorber attenuates the sound level by 20 dB. The intensity decreases
- The pressure at the bottom of a tank containing a liquid does not depend on
- Water falls from a height of 60m at the rate of 15 kg/s to operate a turbine
- An alternating electric field, of frequency v, is applied across the dees (radius = R)
- The velocity of radio-waves is 3×10⁵ km/s. The frequency corresponding to wavelength
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply