The lowest frequency of light that will cause the emission of photoelectrons

The Lowest Frequency Of Light That Will Cause The Emission Physics Question

The lowest frequency of light that will cause the emission of photoelectrons from the surface of a metal (for which work function is 1.65 eV) will be

Options

(a) 4×10¹⁰ Hz
(b) 4×10¹⁴ Hz
(c) 4×10¹¹ Hz
(d) 4×10¹⁵ Hz

Correct Answer:

4×10¹⁴ Hz

Explanation:

Maximum wavelength (in Å) = 12375 / ɸ (in eV)

⇒ λ₀ = 12375 / 1.65 = 7,500 Å = 7.5 × 10⁻⁷ m

Hence minimum frequency = ʋ₀ = c / λ₀

⇒ ʋ₀ = (3 × 10⁸) / (7.5 × 10⁻⁷) = 4 × 10¹⁴ Hz

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Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)

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