The lowest frequency of light that will cause the emission of photoelectrons

⇦

⇨

The lowest frequency of light that will cause the emission of photoelectrons from the surface of a metal (for which work function is 1.65 eV) will be

Options

(a) 4×10¹⁰ Hz
(b) 4×10¹⁴ Hz
(c) 4×10¹¹ Hz
(d) 4×10¹⁵ Hz

Correct Answer:

4×10¹⁴ Hz

Explanation:

Maximum wavelength (in Å) = 12375 / ɸ (in eV)

⇒ λ₀ = 12375 / 1.65 = 7,500 Å = 7.5 × 10⁻⁷ m

Hence minimum frequency = ʋ₀ = c / λ₀

⇒ ʋ₀ = (3 × 10⁸) / (7.5 × 10⁻⁷) = 4 × 10¹⁴ Hz

Related Questions:

1. A boat is sent across a river with a velocity of 8 km/h.If the resultant velocity
2. Two liquid drops having diameters of 1 cm and 1.5 cm. The ratio of excess
3. A potentiometer circuit has been set up for finding the internal resistance of a given
4. The impurity atoms with which pure silicon may be doped to make it a p-type
5. The energy released by the fission of one uranium atom is 200 MeV.

Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends