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The ligand N(CH₂CH₂NH₂)₃ is
Options
(a) tridentate
(b) pentadentate
(c) tetradentate
(d) bidentte
Correct Answer:
tetradentate
Explanation:
Number of donor atoms (N) in N(CH₂CH₂NH₂)₃ is four. So, N(CH₂CH₂NH₂)₃ is a tetradentate ligand.
Related Questions: - For decolourization of 1 mole of KMnO₄, the moles of H₂O₂ required is
- The alkyl halide is converted into an alcohol by
- Intermolecular hydrogen bonding is strongest in
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- Mass of one atom of X is 2.66 x 10⁻²³ g, then its 32 g is equal to
Topics: Coordination Compounds
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For decolourization of 1 mole of KMnO₄, the moles of H₂O₂ required is
- The alkyl halide is converted into an alcohol by
- Intermolecular hydrogen bonding is strongest in
- Potassium is stored in
- Mass of one atom of X is 2.66 x 10⁻²³ g, then its 32 g is equal to
Topics: Coordination Compounds (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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