| ⇦ | 
| ⇨ |
The ionisation energy of an electron in the ground state of helium atom is 24.6 eV. The energy required to remove both the electron is
Options
(a) 51.8 eV
(b) 79 eV
(c) 38.2 eV
(d) 49.2 eV
Correct Answer:
79 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A ray enters a glass sphere of refractive index μ=√3 at an angle of incidence of 60⁰
- A car accelerates from rest at constant rate for first 10s and covers a distance x.
- A galvanometer having resistance of 50 Ω requires a current of 100μA to give full
- In nuclear fission, the percentage of mass converted into energy is about
- A body of mass M hits normally a rigid wall with velocity V and bounces back
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A ray enters a glass sphere of refractive index μ=√3 at an angle of incidence of 60⁰
- A car accelerates from rest at constant rate for first 10s and covers a distance x.
- A galvanometer having resistance of 50 Ω requires a current of 100μA to give full
- In nuclear fission, the percentage of mass converted into energy is about
- A body of mass M hits normally a rigid wall with velocity V and bounces back
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply