| ⇦ |
| ⇨ |
The intensity at the maximum in a Young’s double slit experiment is I₀. Distance between two slits is d=5λ, where λ is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance, D= 10 d?
Options
(a) I₀/4
(b) 3/4 I₀
(c) I₀/2
(d) I₀
Correct Answer:
I₀/2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - 4 point charges each +q is placed on the circumference of a circle
- A simple pendulum is suspended from the ceiling of a lift. When the lift is at rest
- If 20% of a radiactive element decays in 10 days, then amount of original material left
- A wire of length L metre carrying a current I ampere is bent in the form
- In a diffraction pattern due to a singleslit of width a, the first minimum is observed
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 4 point charges each +q is placed on the circumference of a circle
- A simple pendulum is suspended from the ceiling of a lift. When the lift is at rest
- If 20% of a radiactive element decays in 10 days, then amount of original material left
- A wire of length L metre carrying a current I ampere is bent in the form
- In a diffraction pattern due to a singleslit of width a, the first minimum is observed
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply