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The intensity at the maximum in a Young’s double slit experiment is I₀. Distance between two slits is d=5λ, where λ is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance, D= 10 d?
Options
(a) I₀/4
(b) 3/4 I₀
(c) I₀/2
(d) I₀
Correct Answer:
I₀/2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The velocity of a particle performing simple harmonic motion, when it passes
- An object is projected with a velocity of 20 m/s making an angle of 45⁰ with horizontal.
- A long straight wire carrying current of 30A is placed in an external uniform
- One mole of an ideal diatomic gas undergoes a transition from A to B along a path
- Radius of first orbit of the electron in a hydrogen atom is 0.53 Å. So the radius
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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