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The instantaneous angular position of a point on a rotating wheel is given by the equation θ(t) = 2t³ – 6t². The torque on the wheel becomes zero at
Options
(a) t = 1 s
(b) t = 0.5 s
(c) t = 0.25 s
(d) t = 2 s
Correct Answer:
t = 1 s
Explanation:
When angular acceleration is zero then torque on the wheel becomes zero.
θ(t) = 2t – 6t
dθ / dt = 6t – 12t
= dθ / dt = 12t – 12 = 0
t = 1 s
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The wheel of a car is rotating at the rate of 1200 rev/min. On pressing
- Four blocks of same mass connected by cords are pulled by a force F
- The area of cross-section of a steel wire (Y=2.0×10¹¹ N/m²) is 0.1 cm².
- A wheel is rotating at 900 rpm about its axis.When the power is cut-off it
- 4.0 g of a gas occupies 22.4 litres at NTP. The specific heat capacity of the gas
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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