The instantaneous angular position of a point on a rotating wheel is given by

⇦

⇨

The instantaneous angular position of a point on a rotating wheel is given by the equation θ(t) = 2t³ – 6t². The torque on the wheel becomes zero at

Options

(a) t = 1 s
(b) t = 0.5 s
(c) t = 0.25 s
(d) t = 2 s

Correct Answer:

t = 1 s

Explanation:

When angular acceleration is zero then torque on the wheel becomes zero.
θ(t) = 2t – 6t
dθ / dt = 6t – 12t
= dθ / dt = 12t – 12 = 0
t = 1 s

Related Questions:

1. Einstein’s photoelectric equation is
2. A body of mass 3 kg is under a constant force which cause a displacement
3. A nucleus with mass number 220 initially at rest emits an α-particle. If the Q-value
4. A ball rolls off the top of stair way with a horizontal velocity of magnitude 1.8 m/s
5. A particle of mass M is executing oscillations about the origin on the x-axis.

Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends