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The horizontal range of a projectile is 4√3 times the maximum height achieved by it. The angle of projection is
Options
(a) 30⁰
(b) 45⁰
(c) 60⁰
(d) 90⁰
Correct Answer:
30⁰
Explanation:
u²sin 2θ/g = 4√3 x (u²sin 2θ/g ) ⇒ tan θ = 1/√3 .·. θ = 30°
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Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The name of ions knocked out from the hot surface is
- The velocity of molecules of a gas at temperature 120 K is v. At what temperature
- For a simple pendulum performing simple harmonic motion, the time period
- The oscillation of a body on a smooth horizontal surface is represented by the equation
- A thin film of soap solution (n=1.4) lies on the top of a glass plate (n=1.5).
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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