The horizontal range of a projectile is 4√3 times the maximum height achieved

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The horizontal range of a projectile is 4√3 times the maximum height achieved by it. The angle of projection is

Options

(a) 30⁰
(b) 45⁰
(c) 60⁰
(d) 90⁰

Correct Answer:

30⁰

Explanation:

u²sin 2θ/g = 4√3 x (u²sin 2θ/g ) ⇒ tan θ = 1/√3 .·. θ = 30°

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Topics: Motion in Plane (93)
Subject: Physics (2479)

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