| ⇦ | 
| ⇨ |
The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is :
Options
(a) θ = tan⁻¹(1/4)
(b) θ = tan⁻¹(4)
(c) θ = tan⁻¹(2)
(d) θ = 45°
Correct Answer:
θ = tan⁻¹(4)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A particle moves along the x-axis from x=0 to x=5 m under the influence of a force
- The frequencies of X-rays,γ-rays and ultraviolet rays are respectively p,q and r
- The potential difference applied to an X-ray tube is 5 kV and the current through it
- Fission of nuclei is possible because the binding energy per nucleon in them
- A body has 80 microcoulomb of charge. Number of additional electrons in it will be
Difficulty Level: Easy
(1008)
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moves along the x-axis from x=0 to x=5 m under the influence of a force
- The frequencies of X-rays,γ-rays and ultraviolet rays are respectively p,q and r
- The potential difference applied to an X-ray tube is 5 kV and the current through it
- Fission of nuclei is possible because the binding energy per nucleon in them
- A body has 80 microcoulomb of charge. Number of additional electrons in it will be
Difficulty Level: Easy (1008)
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply