| ⇦ | 
| ⇨ |
The horizontal component of earth’s magnetic field at a place is 3×10⁻⁴ T and the dip is tan⁻¹ (4/3). A metal rod of length 0.25m is placed in N-S direction and is moved at a constant speed of 10 cms⁻¹ towards the east. The emf induced in the rod will be
Options
(a) 1μV
(b) 5μV
(c) 7μV
(d) 10μV
Correct Answer:
10μV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- Given A=4i+6j and B=2i+3j. Which of the following is correct?
- A metal plate weighing 750g is to be electroplated with 0.05% of its weight of silver.
- The equivalent resistance of two resistors connected in series is 6 Ω
- A projectile is fired at an angle of 45° with the horizontal
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- Given A=4i+6j and B=2i+3j. Which of the following is correct?
- A metal plate weighing 750g is to be electroplated with 0.05% of its weight of silver.
- The equivalent resistance of two resistors connected in series is 6 Ω
- A projectile is fired at an angle of 45° with the horizontal
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply