| ⇦ | 
| ⇨ |
The frequency of a light wave in a material is 2 x 10¹⁴ Hz and wavelength is 5000Å. The refractive index of material will be
Options
(a) 1.5
(b) 3
(c) 1.33
(d) 1.4
Correct Answer:
3
Explanation:
By using v = nλ , n = 2 x 10¹⁴ Hz
λ = 5000Å = 5000 x 10⁻¹⁰ m
v = 2 x 10¹⁴ x 5000 x 10⁻¹⁰ = 10⁸ m/s
Refractive index of the material,
µ = c / v = 3 x 10⁸ / 10⁸ = 3
Related Questions: - The magnifying power of a telescope is 9. When it is adjusted for parallel rays
- For non-conductors, the energy gap is
- C and Si both have same lattice strcture, having 4 bonding electron in each
- The pressure at the bottom of a tank containing a liquid does not depend on
- A common emitter amplifier is designed with n-p-n transistor (α=0.99).
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The magnifying power of a telescope is 9. When it is adjusted for parallel rays
- For non-conductors, the energy gap is
- C and Si both have same lattice strcture, having 4 bonding electron in each
- The pressure at the bottom of a tank containing a liquid does not depend on
- A common emitter amplifier is designed with n-p-n transistor (α=0.99).
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply