| ⇦ | 
| ⇨ |
The excitation potential of hydrogen atom in the first excited state is
Options
(a) 13.6 V
(b) (-13.6 V)
(c) 10.2 V
(d) (-10 V)
Correct Answer:
10.2 V
Explanation:
Energy of electron in ground state of hydrogen atom,
E₁ = -1.36 eV [E(n) = (-13.6 / n²) eV]
Energy of electron in first excited state of hydrogen atom,
E₂ = -13.6 / 2² = – 3.4 eV
Hence, the excitation energy of hydrogen atom in first excited state,
E = E₂ – E₁ = – 3.4 – (-13.6) = 10.2 eV
Therefore, excitation potential is 10.2 V.
Related Questions: - In a circuit, the current lags behind the voltage by a phase difference of π/2.
- Dimensions of Torque are
- Three blocks A,B and C of masses 4 kg, 2 kg and 1 kg respectively are in contact
- The component of vector A=2i+3j along the vector i+j is
- If the pressure of gas is increased from 1.01×10⁵ Pa to 1.165×10⁵ Pa and volume
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a circuit, the current lags behind the voltage by a phase difference of π/2.
- Dimensions of Torque are
- Three blocks A,B and C of masses 4 kg, 2 kg and 1 kg respectively are in contact
- The component of vector A=2i+3j along the vector i+j is
- If the pressure of gas is increased from 1.01×10⁵ Pa to 1.165×10⁵ Pa and volume
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply