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The excitation potential of hydrogen atom in the first excited state is
Options
(a) 13.6 V
(b) (-13.6 V)
(c) 10.2 V
(d) (-10 V)
Correct Answer:
10.2 V
Explanation:
Energy of electron in ground state of hydrogen atom,
E₁ = -1.36 eV [E(n) = (-13.6 / n²) eV]
Energy of electron in first excited state of hydrogen atom,
E₂ = -13.6 / 2² = – 3.4 eV
Hence, the excitation energy of hydrogen atom in first excited state,
E = E₂ – E₁ = – 3.4 – (-13.6) = 10.2 eV
Therefore, excitation potential is 10.2 V.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- There is a ring of radius r having linear charge densityλ and rotating with a uniform
- Light of wavelength λ is incident on slit of width d. The resulting diffraction
- Energy bands in solids are a consequence of
- Two identical thin plano-convex glass lenses (refractive index 1.5) each having
- A soap bubble oscillates with time period T, which in turn depends on the pressure
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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