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The excitation potential of hydrogen atom in the first excited state is
Options
(a) 13.6 V
(b) (-13.6 V)
(c) 10.2 V
(d) (-10 V)
Correct Answer:
10.2 V
Explanation:
Energy of electron in ground state of hydrogen atom,
E₁ = -1.36 eV [E(n) = (-13.6 / n²) eV]
Energy of electron in first excited state of hydrogen atom,
E₂ = -13.6 / 2² = – 3.4 eV
Hence, the excitation energy of hydrogen atom in first excited state,
E = E₂ – E₁ = – 3.4 – (-13.6) = 10.2 eV
Therefore, excitation potential is 10.2 V.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A source of sound and a detector are moving along the same line with same speed
- The work done in which of the following processes is equal to the change in internal energy
- Dimensions [ML⁻¹T⁻¹] are related with
- The masses of two radioactive substances are same and their half lives
- A tuning fork of frequency 512 Hz makes 4 beats per second with the vibrating string
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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