The equivalent resistance of two resistors connected in series is 6 Ω

⇦

⇨

The equivalent resistance of two resistors connected in series is 6 Ω and their parallel equivalent resistance is 4/3Ω. What are the values of resistances?

Options

(a) 4Ω,6Ω
(b) 8Ω,1Ω
(c) 4Ω,2Ω
(d) 6Ω,2Ω

Correct Answer:

4Ω,2Ω

Explanation:

Let the values of resistance be R₁ and R₂, respectively.
When R₁ and R₂ resistance are series, then
R₁ + R₂ = 6 (according to question) ——(i)
When R₁ and R₂ resistance are parallel, then
R₁R₂ / R₁+R₂ = 4 / 3 ——(ii)
From the equation (i), we get
R₁R₂ / 6 = 4 / 3 ⇒ R₁R₂ = 4 × 3 ⇒ R₁R₂ = 8 —–(iii)
We know that,
R₁ – R₂ = √[(R₁ + R₂)² – 4R₁R₂] = √[36 – 4 × 8] = √4 = 2
From equation (i) and (iv), we get
R₁ = 4 Ω, R₂ = 2 Ω

Related Questions:

1. The energy of the em waves is of the order of 15 keV. To which part of the spectrum
2. During an adiabatic process, the pressure of a gas is found to be proportional
3. 24 cells of emf 1.5 V each having internal resistance of 1 ohm are connected
4. An engine pumps water continuously through a hose. Water leaves the hose
5. Find the maximum velocity with which a train can be moved on a circular track

Topics: Current Electricity (136)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends