| ⇦ | 
| ⇨ |
The energy required to charge a parallel plate condenser of plate separation d and plate area of cross-section A such that the uniform electric field between the plates is E, is
Options
(a) ε₀E² Ad
(b) 1/2 ε₀E² Ad
(c) 1/2 ε₀E²/ Ad
(d) ε₀E² /Ad
Correct Answer:
1/2 ε₀E²/ Ad
Explanation:
The energy required to charge a parallel plate condenser is given by U = 1/2 CV²
As C =ε₀ A / d and V = E.d
U = 1/2ε₀ A / d . E²d²
= 1/2ε₀ E² Ad
Related Questions: - A battery of emf 10 V and internal resistance 3 ohm is connected to a resistor.
- Which of the following is true for number of spectral lines in going from Lyman series
- 4 point charges each +q is placed on the circumference of a circle
- If F⃗ is the force acting on a particle having position vector r⃗ and ? ⃗ be the torque
- Changing magnetic fields can set up current loops in nearby metal bodies
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A battery of emf 10 V and internal resistance 3 ohm is connected to a resistor.
- Which of the following is true for number of spectral lines in going from Lyman series
- 4 point charges each +q is placed on the circumference of a circle
- If F⃗ is the force acting on a particle having position vector r⃗ and ? ⃗ be the torque
- Changing magnetic fields can set up current loops in nearby metal bodies
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply