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The energy required to charge a parallel plate condenser of plate separation d and plate area of cross-section A such that the uniform electric field between the plates is E, is
Options
(a) ε₀E² Ad
(b) 1/2 ε₀E² Ad
(c) 1/2 ε₀E²/ Ad
(d) ε₀E² /Ad
Correct Answer:
1/2 ε₀E²/ Ad
Explanation:
The energy required to charge a parallel plate condenser is given by U = 1/2 CV²
As C =ε₀ A / d and V = E.d
U = 1/2ε₀ A / d . E²d²
= 1/2ε₀ E² Ad
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A transformer rated at 10 kW is used to connect a 5 kV transmission line to a 240 V
- Radius of first orbit of the electron in a hydrogen atom is 0.53 Å. So the radius
- The magnetic field at the centre of a circular coil carrying current I ampere is B.
- Magnetic induction produced at the centre of a circular loop carrying current is B.
- If the image formed by a convex mirror of focal length 30 cm is a quarter of the size
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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