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The energy required to charge a parallel plate condenser of plate separation d and plate area of cross-section A such that the uniform electric field between the plates is E, is
Options
(a) ε₀E² Ad
(b) 1/2 ε₀E² Ad
(c) 1/2 ε₀E²/ Ad
(d) ε₀E² /Ad
Correct Answer:
1/2 ε₀E²/ Ad
Explanation:
The energy required to charge a parallel plate condenser is given by U = 1/2 CV²
As C =ε₀ A / d and V = E.d
U = 1/2ε₀ A / d . E²d²
= 1/2ε₀ E² Ad
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In case of linearly polarised light, the magnitude of the electric field vector
- The number of significant figures in 0.06900
- A 5 watt source emits monochromatic light of wavelength 5000Å. When placed
- Light with an energy flux of 25×10⁴ Wm⁻² falls on a perfectly reflecting surface
- Identify the wrong statement
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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