| ⇦ | 
| ⇨ |
The energy released in the fission of 1 kg of ₉₂U²³⁵ is (energy per fission = 200 MeV)
Options
(a) 5.1 x 10²⁶ eV
(b) 5.1 x 10²⁶ J
(c) 8.2 x 10¹³ J
(d) 8.2 x 10¹³ MeV
Correct Answer:
8.2 x 10¹³ J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A heavy stone hanging from a massless string of length 15 m is projected
- In an ammeter, 0.2% of main current passes through the galvanometer
- A boy is trying to start a fire by focusing sunlight on a piece of paper using
- A remote-sensing satellite of earth revolves in a circular orbit at a height
- A block of mass 4 kg is kept on a rough horizontal surface.The coefficient of static
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A heavy stone hanging from a massless string of length 15 m is projected
- In an ammeter, 0.2% of main current passes through the galvanometer
- A boy is trying to start a fire by focusing sunlight on a piece of paper using
- A remote-sensing satellite of earth revolves in a circular orbit at a height
- A block of mass 4 kg is kept on a rough horizontal surface.The coefficient of static
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply