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The energy of second Bhor orbit of the hydrogen atom is -328 kJ mol⁻¹, hence the enregy of fourth Bohr orbit would be
Options
(a) -41 kJ mol⁻¹
(b) -1312 kJ mol⁻¹
(c) -164 kJ mol⁻¹
(d) -82 kJ mol⁻¹
Correct Answer:
-82 kJ mol⁻¹
Explanation:
The energy of second Bohr orbit of hydrogen atom (E₂) is -328 kJ mol⁻¹therefore,
E₂ = – (1312/2²) kJ mol⁻¹
Eₙ = – (1312/n²) kJ mol⁻¹
If n= 4, E₄ = – (1312/4²) kJ mol⁻¹
= -82 kJ mol⁻¹
Related Questions: - The strongest reducing agent is
- The pH value of 0.02 M ammonia solution, which is 5% ionised, will be
- A bivalent metal has the equivalent weight of 12. The molecular weight
- Which one of the following compounds on nitration easily produces nitro derivative
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Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The strongest reducing agent is
- The pH value of 0.02 M ammonia solution, which is 5% ionised, will be
- A bivalent metal has the equivalent weight of 12. The molecular weight
- Which one of the following compounds on nitration easily produces nitro derivative
- In NH₃ and PH₃, the common feature is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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