| ⇦ |
| ⇨ |
The energy of second Bhor orbit of the hydrogen atom is -328 kJ mol⁻¹, hence the enregy of fourth Bohr orbit would be
Options
(a) -41 kJ mol⁻¹
(b) -1312 kJ mol⁻¹
(c) -164 kJ mol⁻¹
(d) -82 kJ mol⁻¹
Correct Answer:
-82 kJ mol⁻¹
Explanation:
The energy of second Bohr orbit of hydrogen atom (E₂) is -328 kJ mol⁻¹therefore,
E₂ = – (1312/2²) kJ mol⁻¹
Eₙ = – (1312/n²) kJ mol⁻¹
If n= 4, E₄ = – (1312/4²) kJ mol⁻¹
= -82 kJ mol⁻¹
Related Questions: - The π-bond organo metallic compound which has ethene as one of its component is
- Which is used in the preparation of azo-dyes
- Surface tension vanishes at
- In which cell the free energy of a chemical reaction is directly converted into
- Which one of the following explains light both as stream of particle and as wave
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The π-bond organo metallic compound which has ethene as one of its component is
- Which is used in the preparation of azo-dyes
- Surface tension vanishes at
- In which cell the free energy of a chemical reaction is directly converted into
- Which one of the following explains light both as stream of particle and as wave
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply