The energy of second Bhor orbit of the hydrogen atom is -328 kJ mol⁻¹, hence the enregy

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The energy of second Bhor orbit of the hydrogen atom is -328 kJ mol⁻¹, hence the enregy of fourth Bohr orbit would be

Options

(a) -41 kJ mol⁻¹
(b) -1312 kJ mol⁻¹
(c) -164 kJ mol⁻¹
(d) -82 kJ mol⁻¹

Correct Answer:

-82 kJ mol⁻¹

Explanation:

The energy of second Bohr orbit of hydrogen atom (E₂) is -328 kJ mol⁻¹therefore,
E₂ = – (1312/2²) kJ mol⁻¹
Eₙ = – (1312/n²) kJ mol⁻¹
If n= 4, E₄ = – (1312/4²) kJ mol⁻¹
= -82 kJ mol⁻¹

Related Questions:

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Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)

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