The energy of second Bhor orbit of the hydrogen atom is -328 kJ mol⁻¹, hence the enregy

⇦

⇨

The energy of second Bhor orbit of the hydrogen atom is -328 kJ mol⁻¹, hence the enregy of fourth Bohr orbit would be

Options

(a) -41 kJ mol⁻¹
(b) -1312 kJ mol⁻¹
(c) -164 kJ mol⁻¹
(d) -82 kJ mol⁻¹

Correct Answer:

-82 kJ mol⁻¹

Explanation:

The energy of second Bohr orbit of hydrogen atom (E₂) is -328 kJ mol⁻¹therefore,
E₂ = – (1312/2²) kJ mol⁻¹
Eₙ = – (1312/n²) kJ mol⁻¹
If n= 4, E₄ = – (1312/4²) kJ mol⁻¹
= -82 kJ mol⁻¹

Related Questions:

1. Which of the following is a chiral compound
2. The incorrect statement among the following is
3. How many g of silver will be displaced from a solution of AgNO₃ by 4 g of mag
4. The coordination number of Na⁺ in NaCl is
5. In NH₃ and PH₃, the common feature is

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends