The energy of second Bhor orbit of the hydrogen atom is -328 kJ mol⁻¹, hence the enregy

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The energy of second Bhor orbit of the hydrogen atom is -328 kJ mol⁻¹, hence the enregy of fourth Bohr orbit would be

Options

(a) -41 kJ mol⁻¹
(b) -1312 kJ mol⁻¹
(c) -164 kJ mol⁻¹
(d) -82 kJ mol⁻¹

Correct Answer:

-82 kJ mol⁻¹

Explanation:

The energy of second Bohr orbit of hydrogen atom (E₂) is -328 kJ mol⁻¹therefore,
E₂ = – (1312/2²) kJ mol⁻¹
Eₙ = – (1312/n²) kJ mol⁻¹
If n= 4, E₄ = – (1312/4²) kJ mol⁻¹
= -82 kJ mol⁻¹

Related Questions:

1. Which of the following pairs of a chemical reaction is certain to result
2. Property of the alkaline earth metals that increases with their atomic number
3. The law of equilibrium was first given by
4. The combustion enthalpies of carbon , hydrogen and methane are -395.5 kJ mol⁻¹
5. Which one of the following statements regarding photochemical smog is not correct

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)

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