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The energy of a hydrogen atom in the ground state is -13.6 eV. The energy of a He⁺ ion in the first excited state will be
Options
(a) – 13.6 eV
(b) – 27.7 eV
(c) – 54.4 eV
(d) – 6.8 eV
Correct Answer:
– 13.6 eV
Explanation:
energy of a H-like atom in its nth state is given by
E = – Z² x 13.6 / n² eV
For, first excited state of He⁺, n= 2, Z= 2
Eₕₑ⁺ = – 4/2² x 13.6 = – 13.6 eV
Related Questions: - The depth at which the effective value of acceleration due to gravity is g/4
- Electron in hydrogen atom first jumps from third excited state to second excited
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The depth at which the effective value of acceleration due to gravity is g/4
- Electron in hydrogen atom first jumps from third excited state to second excited
- Which of the following statements is correct?
- The maximum and minimum magnitudes of the resultant of two vectors
- In which process, the P-V indicator diagram is a straight line parallel to volume
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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