| ⇦ | 
| ⇨ |
The electric potential V at any point (x,y,z) all in meters in space is given by V = 4x² volt. The electric field at the point (1,0,2) in V/m is
Options
(a) 8 along positive X-axis
(b) 16 along negative X-axis
(c) 16 along positive X-axis
(d) 8 along negative X-axis
Correct Answer:
8 along negative X-axis
Explanation:
E⃗ = – [dv/ dx i + dv/ dy j + dv/ dz k]
= -8 x i V/m
E⃗(1,0,2) = -8i V/m
Related Questions: - If ₉₂U²³⁸ undergoes successively 8 ∝-decays and 6 β-decays, the resulting nucleus is
- A 1 µA beam of protons with a cross-sectional area of 0.5 sq.mm is moving with a velocity
- A sphere of 4cm radius is suspended with in a hollow sphere of 6cm radius. If the inner
- If radius of the ₁₃Al²⁷ nucleus is taken to be Rᴀı, then the radius of ₅₃Te¹²⁵ nucleus
- X-rays when incident on a metal
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If ₉₂U²³⁸ undergoes successively 8 ∝-decays and 6 β-decays, the resulting nucleus is
- A 1 µA beam of protons with a cross-sectional area of 0.5 sq.mm is moving with a velocity
- A sphere of 4cm radius is suspended with in a hollow sphere of 6cm radius. If the inner
- If radius of the ₁₃Al²⁷ nucleus is taken to be Rᴀı, then the radius of ₅₃Te¹²⁵ nucleus
- X-rays when incident on a metal
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply