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The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4. The electric field E⃗ at that point is
Options
(a) E⃗ = i 2xy + j (x² + y²) + k (3xz – y²)
(b) E⃗ = i z³ + j xyz + kz²
(c) E⃗ = i (2xy – z³) + j xy² + k 3z² x
(d) E⃗ = i (2xy + z³) + j x² + k 3xz²
Correct Answer:
E⃗ = i (2xy + z³) + j x² + k 3xz²
Explanation:
The electric field at a point is equal to negative of potential gradient at that point.
E⃗ = – ?V/ ?r = [ -?V/ ?x i – ?V/ ?y j – ?V/ ?z k ]
E⃗ = i (2xy + z³) + j x² + k 3xz²
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A proton is projected with a speed of 3×10⁶ m/s horizontally from east to west.
- What determines the nature of the path followed by the particle?
- A particle having a mass of 10⁻² kg carries a charge of 5 x 10⁻⁸C
- Curie temperature above which
- For a normal eye, the cornea of eye provides a converging power 40 D and the least
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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