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The distance travelled by a particle starting from rest and moving with an acceleration (4/3)ms⁻², in the 3rd second is
Options
(a) 6 m
(b) 4 m
(c) 10/3 m
(d) 19/3 m
Correct Answer:
10/3 m
Explanation:
Distance travelled in the nth second is given by tₙ = u + a/2 (2n – 1)
put u= 0, a= 4/3 ms⁻², n= 3
d= 0 + 4/ 3×2 (2 x 3 – 1) = 4/6 x 5 = 10/ 3 m
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Question Type: Apply
(15)
Difficulty Level: Easy
(1008)
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For a wave propagating in a medium, identify the property that is independent
- A charge of 100 μC has a potential at a distance of 9 m is
- If a given volume of water in a 220V heater is boiled in 5 min, then same volume
- In a n-type semiconductor, which of the following statement is true?
- The number of beta particles emitted by a radioactive substance is twice the number
Question Type: Apply (15)
Difficulty Level: Easy (1008)
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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