| ⇦ |
| ⇨ |
The distance travelled by a particle starting from rest and moving with an acceleration (4/3)ms⁻², in the 3rd second is
Options
(a) 6 m
(b) 4 m
(c) 10/3 m
(d) 19/3 m
Correct Answer:
10/3 m
Explanation:
Distance travelled in the nth second is given by tₙ = u + a/2 (2n – 1)
put u= 0, a= 4/3 ms⁻², n= 3
d= 0 + 4/ 3×2 (2 x 3 – 1) = 4/6 x 5 = 10/ 3 m
Related Questions: - Electrical force is acting between two charges kept in vacuum. A copper plate
- A particle under the action of a constant force moves from rest upto 20 seconds
- When the length of the vibrating segment of a sonometer wire is increased by
- Two sources P and Q produce notes of frequency 660 Hz each.
- The equiconvex lens has focal length f. If it is cut perpendicular to the principal
Question Type: Apply
(15)
Difficulty Level: Easy
(1008)
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Electrical force is acting between two charges kept in vacuum. A copper plate
- A particle under the action of a constant force moves from rest upto 20 seconds
- When the length of the vibrating segment of a sonometer wire is increased by
- Two sources P and Q produce notes of frequency 660 Hz each.
- The equiconvex lens has focal length f. If it is cut perpendicular to the principal
Question Type: Apply (15)
Difficulty Level: Easy (1008)
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply