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The distance travelled by a particle starting from rest and moving with an acceleration (4/3)ms⁻², in the 3rd second is
Options
(a) 6 m
(b) 4 m
(c) 10/3 m
(d) 19/3 m
Correct Answer:
10/3 m
Explanation:
Distance travelled in the nth second is given by tₙ = u + a/2 (2n – 1)
put u= 0, a= 4/3 ms⁻², n= 3
d= 0 + 4/ 3×2 (2 x 3 – 1) = 4/6 x 5 = 10/ 3 m
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Question Type: Apply
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Difficulty Level: Easy
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Topics: Motion in Straight Line
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The time period of a thin bar magnet in Earth’s magnetic field is T
- An artificial satellite is revolving round the earth in a circular orbit. Its velocity
- A body of mass 3 kg is under a constant force which cause a displacement
- The velocity of a particle at an instant is 10 ms⁻¹ and after 5 s the velocity
- The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field
Question Type: Apply (15)
Difficulty Level: Easy (1008)
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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