| ⇦ | 
| ⇨ |
The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one dimension under the action of a force, is related to time ‘t’ (in sec) by t = √x + 3. The displacement of the particle when its velocity is zero, will be
Options
(a) 2 m
(b) 4 m
(c) zero
(d) 6 m
Correct Answer:
zero
Explanation:
t = √x + 3
⇒ √x = t – 3 ⇒ x = (t – 3)²
v = dx/ dt = 2 (t – 3) = 0 ⇒ t = 3
x = (3 – 3)² ⇒ x = 0.
Related Questions: - According to Hook’s law, force is proportional to
- At what temperature will the rms speed of air molecules be double that of NTP?
- For a normal eye, the cornea of eye provides a converging power 40 D and the least
- For CE transistor amplifier, the audio signal voltage across the collector resistance
- A force F=ai+3j+6k is acting at a point r=2i-6j-12k. The value of α for
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- According to Hook’s law, force is proportional to
- At what temperature will the rms speed of air molecules be double that of NTP?
- For a normal eye, the cornea of eye provides a converging power 40 D and the least
- For CE transistor amplifier, the audio signal voltage across the collector resistance
- A force F=ai+3j+6k is acting at a point r=2i-6j-12k. The value of α for
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply