⇦ | ![]() | ⇨ |
The displacement of a particle varies according to the relation x=4 (cos π t + sin π t). The amplitude of the particle is
Options
(a) 8
(b) -4
(c) 4
(d) 4 √2
Correct Answer:
4 √2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- A particle under the action of a constant force moves from rest upto 20 seconds
- Electric potential at any point is V= -5x +3y + √(15) z. Then the magnitude of electric
- A transistor is working in common emitter mode. Its amplification factor is 80
- When sound is produced in an aeroplane with a velocity of 200 m/s horizontally,
- 6Ω and 12Ω resistors are connected in parallel. This combination is connected
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply