| ⇦ | 
| ⇨ |
The dimensions of mobility of charge carriers are
Options
(a) [M⁻²T²A]
(b) [M⁻¹T²A]
(c) [M⁻²T³A]
(d) [M⁻¹T³A]
Correct Answer:
[M⁻¹T²A]
Explanation:
Mobility = drift velocity / electric field
μ = v(d) / E = metre² / volt-second = [L]² / (joule/coulomb)-second
= [L]² / [(kg-metre² – sec²)-second / ampere-second] = [L]² / [ML²T⁻²A⁻¹] = [M⁻¹T²A]
Related Questions: - A proton and an alpha particle both enter a region of uniform magnetic field B,
- In p- type semiconductor, the acceptor level lies
- In communication with help of antenna if height is doubled then the range
- Electron in hydrogen atom first jumps from third excited state to second excited
- The quantity having the same units in all systems of unit is
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A proton and an alpha particle both enter a region of uniform magnetic field B,
- In p- type semiconductor, the acceptor level lies
- In communication with help of antenna if height is doubled then the range
- Electron in hydrogen atom first jumps from third excited state to second excited
- The quantity having the same units in all systems of unit is
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply