| ⇦ |
| ⇨ |
The dimensions of magnetic field intensity B are
Options
(a) MLT⁻²A⁻¹
(b) MT⁻²A⁻¹
(c) ML²TA⁻²
(d) M²LT⁻²A⁻¹
Correct Answer:
MT⁻²A⁻¹
Explanation:
Dimensions of B = [MT⁻²A⁻¹]
F = Bil sin θ
[MLT⁻²] = [B] [AL]
[B] = [MT⁻²A⁻¹]
Related Questions: - When aluminium is added as an impurity to silicon, the resulting material is
- An air core solenoid has 1000 turns and is one meter long. Its cross sectional area
- Two planets at mean distances d₁ and d₂ from the sun have their frequencies n₁ and n₂
- The ratio of specific heats Cp/Cv=γ in terms of degrees of freedom (n) is given by
- A small rod of bismuth is suspended freely between the poles of a strong electromagnet.
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When aluminium is added as an impurity to silicon, the resulting material is
- An air core solenoid has 1000 turns and is one meter long. Its cross sectional area
- Two planets at mean distances d₁ and d₂ from the sun have their frequencies n₁ and n₂
- The ratio of specific heats Cp/Cv=γ in terms of degrees of freedom (n) is given by
- A small rod of bismuth is suspended freely between the poles of a strong electromagnet.
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply