| ⇦ | 
| ⇨ |
The difference between ΔH and ΔE at 300 K for the reaction
C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)
Options
(a) 300 ˣ 8.31 J/mol
(b) -300 ˣ 8.314 J/mol
(c) 3 ˣ 300 ˣ 8.314 J/mol
(d) -3 ˣ 300 ˣ 8.314 J/mol
Correct Answer:
-3 ˣ 300 ˣ 8.314 J/mol
Explanation:
ΔH = ΔE + Δn(g)RT
or ΔH – ΔE = Δn(g)RT,
where Δn(g) = (3) – (5 + 1) = -3.
Thus, ΔH – ΔE = -3 * 8.31 *300 J/mol.
Related Questions: - One gram sample NH₄NO₃ is decomposed in a bomb calorimeter.
- If a is the length of the side of a cube the distance between the body
- On treating a mixture of two alkyl halides with sodium metal in dry ether,
- Which of the following is an antibiotic
- What is the [OH⁻] in the final solution prepared by mixing 20 mL of 0.05 M Hcl
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- One gram sample NH₄NO₃ is decomposed in a bomb calorimeter.
- If a is the length of the side of a cube the distance between the body
- On treating a mixture of two alkyl halides with sodium metal in dry ether,
- Which of the following is an antibiotic
- What is the [OH⁻] in the final solution prepared by mixing 20 mL of 0.05 M Hcl
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply