| ⇦ | 
| ⇨ |
The difference between ΔH and ΔE at 300 K for the reaction
C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)
Options
(a) 300 ˣ 8.31 J/mol
(b) -300 ˣ 8.314 J/mol
(c) 3 ˣ 300 ˣ 8.314 J/mol
(d) -3 ˣ 300 ˣ 8.314 J/mol
Correct Answer:
-3 ˣ 300 ˣ 8.314 J/mol
Explanation:
ΔH = ΔE + Δn(g)RT
or ΔH – ΔE = Δn(g)RT,
where Δn(g) = (3) – (5 + 1) = -3.
Thus, ΔH – ΔE = -3 * 8.31 *300 J/mol.
Related Questions: - The preparation of ethene from ethanol can be described as
- In a given atom no two electrons can have the same values for all
- IN Haber process 30 L of dihydrogen and 30 L of dinitrogen were taken for reaction
- Number of isomers of C₄H₁₀ is
- Melting point is the higher for
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The preparation of ethene from ethanol can be described as
- In a given atom no two electrons can have the same values for all
- IN Haber process 30 L of dihydrogen and 30 L of dinitrogen were taken for reaction
- Number of isomers of C₄H₁₀ is
- Melting point is the higher for
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply