| ⇦ |
| ⇨ |
The difference between ΔH and ΔE at 300 K for the reaction
C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)
Options
(a) 300 ˣ 8.31 J/mol
(b) -300 ˣ 8.314 J/mol
(c) 3 ˣ 300 ˣ 8.314 J/mol
(d) -3 ˣ 300 ˣ 8.314 J/mol
Correct Answer:
-3 ˣ 300 ˣ 8.314 J/mol
Explanation:
ΔH = ΔE + Δn(g)RT
or ΔH – ΔE = Δn(g)RT,
where Δn(g) = (3) – (5 + 1) = -3.
Thus, ΔH – ΔE = -3 * 8.31 *300 J/mol.
Related Questions: - In the titration of strong acid and weak base, the indicator used is
- General electronic configuration of lanthanides is
- The oxidation number of phosphorus and basicity of acid in pyrophosphoric acid
- Bleaching powder is obtained by treating chloride with
- The inert gas abundantly found in atmosphere is
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the titration of strong acid and weak base, the indicator used is
- General electronic configuration of lanthanides is
- The oxidation number of phosphorus and basicity of acid in pyrophosphoric acid
- Bleaching powder is obtained by treating chloride with
- The inert gas abundantly found in atmosphere is
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply