Navigate

The diameter of the eye ball of a normal eye is about 2.5 cm. The power of the eye

The diameter of the eye ball of a normal eye is about 2.5 cm. The power of the eye lens varies from

Options

(a) 9 D to 8 D
(b) 40 D to 32 D
(c) 44 D to 40 D
(d) None of these

Correct Answer:

44 D to 40 D

Explanation:

An eye see distant objects with full relaxation.

So, [1 / (2.5 × 10⁻²)] – [1 / -∞] = 1 / f or, P = 1 / f = 1 / 2.5 × 10⁻² = 40 D

An eye see an object at 25 cm with strain [1 / (2.5 × 10⁻²)] – [1 / 2.5 × 10⁻²] = 1 / f

.·. P = 1 / f = 40 + 4 = 44 D

BCE2012
admin:

Related Questions

  1. When aluminium is added as an impurity to silicon, the resulting material is
  2. The physical quantity which does not have the same dimensions as the other three is
  3. A particle of mass m is projected with a velocity v making an angle of 45°
  4. If critical angle for a material to air passage is 30°, the refractive index
  5. A ray of light passes from a medium A having refractive index 1.6 to the medium