| ⇦ | 
| ⇨ |
The diameter of the eye ball of a normal eye is about 2.5 cm. The power of the eye lens varies from
Options
(a) 9 D to 8 D
(b) 40 D to 32 D
(c) 44 D to 40 D
(d) None of these
Correct Answer:
44 D to 40 D
Explanation:
An eye see distant objects with full relaxation.
So, [1 / (2.5 × 10⁻²)] – [1 / -∞] = 1 / f or, P = 1 / f = 1 / 2.5 × 10⁻² = 40 D
An eye see an object at 25 cm with strain [1 / (2.5 × 10⁻²)] – [1 / 2.5 × 10⁻²] = 1 / f
.·. P = 1 / f = 40 + 4 = 44 D
Related Questions: - A choke is preferred to a resistance for limiting current in AC circuit because
- On observing light from three different stars P, Q and R, it was found that intensity
- Calcium plate has a maximum possible radiation wavelength 400 nm to eject electrons.
- The velocity of radio-waves is 3×10⁵ km/s. The frequency corresponding to wavelength
- In a semiconductor
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A choke is preferred to a resistance for limiting current in AC circuit because
- On observing light from three different stars P, Q and R, it was found that intensity
- Calcium plate has a maximum possible radiation wavelength 400 nm to eject electrons.
- The velocity of radio-waves is 3×10⁵ km/s. The frequency corresponding to wavelength
- In a semiconductor
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply